note 35378 deleted from language.variables.variable by nlopess
| From: | nlopess@php.net | Date: | Sat, 22 May 2004 08:17:38 +0000 |
| Subject: | note 35378 deleted from language.variables.variable by nlopess | ||
| References: | 1 | Groups: | php.notes |
| Request: | Send a blank email to php-notes+get-69939@lists.php.net to get a copy of this message | ||
Note Submitter: Stoker overatthe sauen d com
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Using variable variables with arrays, I've been searching quite a bit for it and have not found
any solutions, and the comments here indicate the same as what i found, that
$myarray = array ('Sierra Nevada','Sam Adams');
$arraypath = 'myarray[0]';
echo ${$arraypath};
does not work (at least not in PHP 4.3.2).
A "dirty" workaround is to use eval, but be careful and do not use submitted data in the
eval statement directly (Security)..
Instead of the echo above you could do something like
eval ('$myval = $'.$arraypath.';');
echo $myval;
(Could also do echo in the eval, depending on what you need the value for)