note 40147 added to function.printf

This may seem obvious but the variable swapping feature of printf, ie:- <?php $format = "The %2\$s contains %1\$d monkeys. That is a nice %2\$s full of %1\$d monkeys."; printf($format, $num, $location); ?> Does not work with single quotes, ie:- <?php $format = 'The %2\$s contains %1\$d monkeys. That is a nice %2\$s full of %1\$d monkeys.'; printf($format, $num, $location); ?> You will get an error complaining about too few arguments, always use double quotes for variable swapping ---- Manual Page -- http://www.php.net/manual/en/function.printf.php Edit -- http://master.php.net/manage/user-notes.php?action=edit+40147 Delete -- http://master.php.net/manage/user-notes.php?action=delete+40147&report=yes Reject -- http://master.php.net/manage/user-notes.php?action=reject+40147&report=yes Search -- http://master.php.net/manage/user-notes.php