note 42768 deleted from function.preg-replace by nlopess
| From: | nlopess@php.net | Date: | Fri, 28 May 2004 15:19:49 +0000 |
| Subject: | note 42768 deleted from function.preg-replace by nlopess | ||
| References: | 1 | Groups: | php.notes |
| Request: | Send a blank email to php-notes+get-70247@lists.php.net to get a copy of this message | ||
Note Submitter: dennis_hilhorst AT zonnet DOT nl
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I want the following sting
'<font face="courier new" color=#006600 size=6>Courier new</font> is not
equal to <font face=arial color=#006600 size=6>Arial</font>'
converted in
'<font face="courier new" color="#006600" size="6">Courier
new</font> is not equal to <font face="arial" color="#006600"
size="6">Arial</font>'
I want in this example the value of the face/color/size between 2 ""... I just don't
know what the right syntax is for this problem...
Who can help me???
<?
$input = '<font face="courier new" color=#006600 size=6>Courier
new</font> is niet gelijk aan <font face=arial color=#006600
size=6>Arial</font>';
$output = preg_replace(); // <- ! ! !
?>