Re: DataObject update

On Thu, 17 Mar 2005 19:12:30 +0100, Esad Hajdarevic <esad-public@25novembar.com> wrote: > Justin Patrin wrote: > > > Just expaning on the "edge case" idea. This *is* an edge case. If you > > have two DataObjects which represent the same record you're probably > > not using DB_DataObject correctly. It makes much more sense to use two > > copied of the same DO. > > $do =& DB_DataObject::factory('table'); > > $do->get(5); > > ... > > $do2 =& $do; > > $do2->col = 'val'; > > I think we misunderstood each other. > I'm talking about something like: > > <code> > > $d=new DataObjects_Dealer; > > $fb=& DB_DataObject_FormBuilder::create($d); > $form =& $fb->getForm(); > > if ($form->validate()) { > $form->process(array(&$fb,'processForm'), false); > } > > //at this point form is validated an the dataobject is processed > //now I have to show the list of all dealers > > $d->find(); > while ($d->fetch()) { > ... > } > > </code> > > The $d->find() wont work because of the data object manipulation done > by processForm. > > So instead of typing something like > > $d->rewind(); > > one has to create new data object? > Ok, this is a different case. In this case, that DataObject has alreayd been used for a specific record and cannot be re-used for a find()/fetch() unless you unset its member vars. It's generally bad practice, though, to use the same dataobject for multiple different uses. -- Justin Patrin