Re: [ANNOUNCEMENT] DB-1.7.13 (stable) Released.
| From: | Craig Constantine | Date: | Sun, 23 Sep 2007 20:39:12 +0000 |
| Subject: | Re: [ANNOUNCEMENT] DB-1.7.13 (stable) Released. | ||
| References: | 1 | Groups: | php.pear.dev |
| Request: | Send a blank email to pear-dev+get-48134@lists.php.net to get a copy of this message | ||
--On September 21, 2007 Sep 21, 15:16.43 +0000 PEAR Announce
<pear-dev@lists.php.net> wrote:
> * Replaced instances of '=& new Foo' with '= new Foo' to make DB
> (slightly)
> more E_STRICT friendly. Request 11581.
All,
Could someone hit me with the clue-bat on this. just send me off to rtfm if
this is explained clearly in one spot. :)
I know that "$x =& new Foo()" is 'out' in php5.
but in PHP4, the "$x =& new Foo" construct used to make a new Foo instance,
then make $x refer to that instance. And "$x = new Foo" use to make a new Foo,
then make $x be a *copy* of that new Foo. I have this vague recollection of
falling over this in some project. I had used the "$x = new Foo" contruct and
took me a while to discover there were really two Foo instances in that one
line of code. When I changed to =& my problem was resolved. So I dutifully
started "=& new" all my objects in php4
so my questions:
- is my understanding above, in php4 context, correct? (I have legacty code to
maintain ya know.)
- and how does "$x = new Foo" work in php5? does it 'just work correctly' thus
we no longer needed the "$x =& new Foo" from php4.
-c