RE: [PEAR][DB][DataObject] links.ini

I don't use getLinks() much, but I think what you want, after calling getLinks() is to use the related table's key name, not the calling table's foreign key name, so "$person->_ID->name" instead of "$person->_affiliationID->name"...but that's not tested and I could be wrong. Andy > -----Original Message----- > From: Matthias H. Risse [mailto:risse@risse.org] > Sent: Thursday, September 11, 2003 5:36 PM > To: Andy Crain; pear-general@lists.php.net > Subject: re: [PEAR][DB][DataObject] links.ini > > > hi andy, hi all others! > finally here is my derived code from > the manpages. what's my problem? > > // ################################################################ > // code > // ################################################################ > > $person = new DataObjects_Users; > $person->affiliationID = '1'; > > /* > // without links.ini > // works > $person->find(); > while ($person->fetch()) { > // this will look up in the cars table for the id matching > the > person->car value. > > $organization = $person- > >getLink('affiliationID','Organization','ID'); > > echo "{$person->login} is associated with > {$organization->name}<br>\n"; > > echo "<br><br>"; > print_r($organization); > echo "<br><br>"; > > } > */ > > // with links.ini > // doesnt work > $person->find(); > while ($person->fetch()) { > > // use the links.ini file to automatically load > // the car object into $person->_car <<<< EH? well.. > $person->getLinks(); > echo "{$person->login} loves to work at > {$person->_affiliationID->name}\n<br><br>"; > print_r($person); > echo "<br><br>"; > } > ?> > > > // ################################################################ > // mydbname.links.ini > // ################################################################ > > [users] > affiliationID = organization:ID