Re: [PHP4BETA] broken or probably not implement!

: I'm not sure what you're saying here, all of the results reported by PHP : are correct. 10||1 is true (boolean). The fact that Perl reports 10 is Then why: $str = 10 or 1 // = 10 and $str = 0 or 1 // = 0 0 is false, and 'or' has low precedence, so result should be 1! Also: $str = 0 || 1 // = 0 $str = "" or "faisal"; // "" In Perl, it will behave as a conditional operator and won't return the boolean match: $str = "" || "faisal"; // faisal $str = "" or "faisal"; // "" BITWISE: print "" | "faisal"; // "" print 10 | 100; // 110 All I was trying to simplify this: $str = (int) $blah; if ( ! $str ) $str = 0; Perl: $str = int $blah || 0; PHP: $str = (int) $blah ? $blah : 0; OR: $total = somelongfunction ( $arg ); if ( ! $total ) $total = 100; Because this will be silly to call our *long* function twice like this: $total = somelongfunction ( $arg ) ? somelongfunction ( $arg ) : 100; Where, in Perl I can: $total = &somelongfunction || 100; # not returning boolean value! : meaningless, any value that translates into true is valid. If you want to : conduct bitwise operations, you should be using the bitwise operators, : i.e. 10|1. : : : Zeev : : On Fri, 18 Feb 2000, Faisal Nasim wrote: : : > Greetings, : > : > PHP could use some more flexibility and some bug fixing! : > : > $str = 10 || 1; // 1 : > $str = 0 || 1; // 1 ... correct : > $str = 10 or 1; // 10 ... correct : > $str = 0 or 1; // 0 : > : > : > Either PHP doesn't support them well now, or its completely : > broken! Any info? : > : > Perl reports: : > : > 10 ... correct : > 1 ... correct : > 10 ... correct : > 0 ... correct, according to the precedence table, I reckon. : > : > Thank you! :