Re: [PHP4BETA] Latest CVS - Question

Dustin Marquess [jailbird@alcatraz.fdf.net] wrote: > > > > However, if I put $db as the link identifer in mysql_select_db I get the > > document contains no data error. I do not know if this is an error or > > intentional. > > Probably because you are assigning $db the result of the > mysql_connect, which is a MySQL data structure. mysql_select_db() wants > the name of the database you want to select, not the structure. Try: > > $blah = "pcstuff"; > @mysql_select_db($blah) or die("Could not select database."); I hear what you are saying and it works, just like my code snippet does. However, if you include the link identifer in the mysql_select_db statement it gives the document comtains no data error message. Not very useful when I have 2 or more databases open at once. The following code taken directly from the Core Programming Book (with my echo statement) has the same problem : (I created a temp database called store). <? $mysql_link = mysql_connect("localhost", "root", ""); mysql_select_db("store",$mysql_link); echo "Boo!"; ?> Even putting : $blah = "store"; mysql_select_db($blah, $mysql_link); gives the error. Having the link identifer in the select_db statement worked fine until a CVS download yesterday. If the format of the command has changed then fine, but to me it looks like a possible problem. -- Sarah Pearson sarah@zippysoft.com