Re: Re: &$this?

Hi _lallous, yes, but I think he knew this already. the question is that since $this itself is a reference to the object, why inside the class still need to assign the address of $this to $globalref[]? -- regards, chen wei (http://www.cw213.net) =================================== Solutions Developer of Earth9.com =================================== Wednesday, September 26, 2001, 6:45:15 PM, you wrote: _> &$varname menas to take the address of the variable, _> example: _> $a = "Hello world!"; _> $b = &$a; _> $b = "Hi! this is var B"; _> echo $a; _> // output will be: Hi! this is var B _> "Ming-Chieh Lee" <ming@thesmartport.com> wrote in message _> news:20010925194957.34536.qmail@pb1.pair.com... >> does anyone know what does &$this mean? I saw this on the php.net _> tuturial >> for references inside a constructor. >> I thought that $this is already a reference? >> The way it was used : >> class Foo >> { >> function Foo($name) >> { >> // create a reference inside the global array $globalref >> global $globalref; >> $globalref[] = &$this; >> // set name to passed value >> $this->setName($name); >> // and put it out >> $this->echoName(); >> } >> thanks for any input! >> >> >>