Re: Re: &$this?

Hello all, Thanks for the input. Chen Wei, thanks for clarifying my question. So why do we need to make a reference out of a variable that already contains a reference? I Thanks for any input! "Chen Wei" <chenwei@earth9.com> wrote in message news:120453264830.20010926180143@earth9.com... > Hi _lallous, > > yes, but I think he knew this already. the question is that since $this > itself is a reference to the object, why inside the class still need to > assign the address of $this to $globalref[]? > > > -- > regards, > chen wei (http://www.cw213.net) > =================================== > Solutions Developer of Earth9.com > =================================== > > > Wednesday, September 26, 2001, 6:45:15 PM, you wrote: > > _> &$varname menas to take the address of the variable, > > _> example: > > _> $a = "Hello world!"; > _> $b = &$a; > _> $b = "Hi! this is var B"; > _> echo $a; > > _> // output will be: Hi! this is var B > > _> "Ming-Chieh Lee" <ming@thesmartport.com> wrote in message > _> news:20010925194957.34536.qmail@pb1.pair.com... > >> does anyone know what does &$this mean? I saw this on the php.net > _> tuturial > >> for references inside a constructor. > >> I thought that $this is already a reference? > >> The way it was used : > >> class Foo > >> { > >> function Foo($name) > >> { > >> // create a reference inside the global array $globalref > >> global $globalref; > >> $globalref[] = &$this; > >> // set name to passed value > >> $this->setName($name); > >> // and put it out > >> $this->echoName(); > >> } > >> thanks for any input! > >> > >> > >> >