Re: PHP 4.0 Bug #6240: is_reference()

From: Date: Fri, 18 Aug 2000 20:49:33 +0000
Subject: Re: PHP 4.0 Bug #6240: is_reference()
References: 1  Groups: php.dev 
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I know which variable (zval) I have visited. But zval's and $var in PHP are different thing. zval is a C pointer, and $var is a PHP syntax construct and a symbol table entry. There's no easy way (short of remembering full path back in every point of var_dump where I move in) to move from zval to $var, and outside var_dump there's no way *at all* to get $var having zval.
Just keep me informed which mechanism you´ve invented (as far as you´re onit), I can only tell you what makes most sense for the PHP developer to see in var_dump() not more not less, you´re closer to the system.... -- o----------0-¬---------O-·---¬----o---®-----o o O ° . | http://www.kiffen.de | pRoteçt y0ur bRaín |0 O ° ¤ ° · 0°·³°²'²³-¹'³´³°^°³~³²³°'³²²¨³²^³¹³²°²³`³º³°Þ ° o © ° . · | psychedelic experience | gott@kiffen.de | O ° o ° o-¬--o--0-----©-·--O-----o-----0-¤----------o 0 ° · ° . ¤ ·

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