Bug #14747 Updated: Return exitcodes to shell ($?)
| From: | derick@php.net | Date: | Sat, 29 Dec 2001 20:27:22 +0000 |
| Subject: | Bug #14747 Updated: Return exitcodes to shell ($?) | ||
| References: | 1 | Groups: | php.dev |
| Request: | Send a blank email to php-dev+get-75290@lists.php.net to get a copy of this message | ||
ID: 14747
Updated by: derick
Reported By: bernd.herbold@gmx.de
Old Status: Open
Status: Suspended
Bug Type: Feature/Change Request
Operating System:
PHP Version: 4.1.1
New Comment:
just use exit(number)
it returns the exit code (and also prints the value). The printing will be removed in PHP5 (if it is
a number).
Derick
Previous Comments:
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[2001-12-28 16:39:37] bernd.herbold@gmx.de
Hi,
I tried to use PHP in connection with shellprogramming.
I would be fine if you could return exit codes to shellscripts. So that you can use something like
"if [ $? -eq 0 ]" to test if the PHP-Script had run succesful.
So wouldn`t need to use Perl in future.
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Edit this bug report at http://bugs.php.net/?id=14747&edit=1