Re: regex

From: Date: Sun, 23 Mar 2003 02:17:22 +0000
Subject: Re: regex
References: 1  Groups: php.general 
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Try this (entirely untested!): $final_footer = preg_replace('%INCLUDE_FILE\\[[^\\]]*\\]%','',$final_footer); Nate wrote:
hi, i need to search $final_footer for a string such as %INCLUDE_FILE[/path/to/file]% (where /path/to/file could be anything) and delete it from the string. it being %INCLUDE_FILE[/path/to/file]% (not just /path/to/file) im new to regexps but im guessing I should use preg_match for this? Can someone give me a code example? thanks much Nate
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