Re: regex

Thanks! That worked almost. It removed everything except for the 2 % signs. How might I remove those as well? "Leif K-Brooks" <eurleif@buyer-brokerage.com> wrote in message news:<3E7D1932.2030400@buyer-brokerage.com>... > Try this (entirely untested!): > $final_footer = > preg_replace('%INCLUDE_FILE\\[[^\\]]*\\]%','',$final_footer); > > Nate wrote: > > >hi, > > > >i need to search $final_footer for a string such as > >%INCLUDE_FILE[/path/to/file]% (where /path/to/file could be anything) > >and delete it from the string. it being %INCLUDE_FILE[/path/to/file]% > >(not just > >/path/to/file) > > > >im new to regexps but im guessing I should use preg_match for this? > > > >Can someone give me a code example? > > > >thanks much > >Nate > > > > > > > > > > > > -- > The above message is encrypted with double rot13 encoding. Any unauthorized attempt to decrypt it will be prosecuted to the full extent of the law. > > >