Re: regex

From: Date: Sun, 23 Mar 2003 02:35:47 +0000
Subject: Re: regex
References: 1  Groups: php.general 
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Whoops! Try this: preg_replace('|%INCLUDE_FILE\\[[^\\]]*\\]%|','',$final_footer); Nate Sanden wrote:
Thanks! That worked almost. It removed everything except for the 2 % signs. How might I remove those as well? "Leif K-Brooks" <eurleif@buyer-brokerage.com> wrote in message news:3E7D1932.2030400@buyer-brokerage.com...
Try this (entirely untested!): $final_footer = preg_replace('%INCLUDE_FILE\\[[^\\]]*\\]%','',$final_footer); Nate wrote:
hi, i need to search $final_footer for a string such as %INCLUDE_FILE[/path/to/file]% (where /path/to/file could be anything) and delete it from the string. it being %INCLUDE_FILE[/path/to/file]% (not
     
just
/path/to/file) im new to regexps but im guessing I should use preg_match for this? Can someone give me a code example? thanks much Nate
     
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