Re: get image size function

Here's where I initialize my variables $data_file = "pictures/pictures/list.photos"; $thumbnail_dir = "pictures/thumbs/"; $num_rows = 4; $photos_per_row = 5; $photos = file($data_file); $total_photos = sizeof($photos); $photos_per_page = $num_rows * $photos_per_row; When I echo/print the variables everything goes well until I get to $photos = file($data_file); That's when I get a value of array. Anybody got any idea why this is doing this?

From: John Dempsey <dempsejn@gusun.georgetown.edu> To: Tyler Durdin <linuxgeek23@hotmail.com> CC: php-general@lists.php.net Subject: Re: [PHP] get image size function Date: Wed, 9 Apr 2003 15:38:47 -0400 (EDT) ok, so that looks like its not finding the file given in your photo array...not to doubt you, but are you sure you're getting the full filename, extension included, in the array, and that the file's actually in the same directory? try a test with file_exists to make sure its there, and print out what the trim($photos[$i]) value is to double check what's happening... jack On Wed, 9 Apr 2003, Tyler Durdin wrote: I ran the print_r and sure enough all of the image values were there. So now I am stuck again. This is the error message I am getting: Warning: getimagesize(Mvc-038f.jpg) [function.getimagesize]: failed to create stream: No such file or directory in /www/servers/comgo_test/gallery.php on line 47 And this is line 47 $image_size = getimagesize(trim($photos[$i])); These are the variables the line is referring to $photos = file($data_file); ** the datafile just has the names of 3 jpg images **

From: dempsejn@georgetown.edu To: "Tyler Durdin" <linuxgeek23@hotmail.com> CC: php-general@lists.php.net Subject: Re: [PHP] get image size function Date: Wed, 09 Apr 2003 14:17:06 -0400 hey tyler, just looking at that quickly, i'd try testing it with print_r to see the structure; if you're getting the string "Array" then its obviously an array that you have to then select something from. print_r($var) should make it clear. jack ----- Original Message ----- From: "Tyler Durdin" <linuxgeek23@hotmail.com> Date: Wednesday, April 9, 2003 2:13 pm Subject: [PHP] get image size function

When I run this script: <?php $size = getimagesize ("pictures/pictures/bobby.jpg"); echo "<img src=\"pictures/pictures/bobby.jpg\" {$size[3]}>"; ?> I get Array (the word Array) and a picture of the image. Why am I not getting the image size? Did I not configure php to use the image functions? If that's the case how can I correct this problem? If it's not the case what is going on here? Please help!!! _________________________________________________________________ Protect your PC - get McAfee.com VirusScan Online http://clinic.mcafee.com/clinic/ibuy/campaign.asp?cid=3963 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php

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