RE: [PHP] get image size function

ok, looking at that, i'd say a few things: first, its easier if you have .phps enabled, so the source is nice and colorized :-) also, on the lines that seem to work, you do: $thumbnail = $thumbnail_dir.trim($photos[$i]); $thumb_image_size = getimagesize($thumbnail); $image_size = getimagesize(trim($photos[$i])); having set $thumbnail_dir previously. but then you try to get the image of the photo without giving the complete directory for it...try that and let me know... jack > -----Original Message----- > From: Tyler Durdin [mailto:linuxgeek23@hotmail.com] > Sent: Wednesday, April 09, 2003 4:37 PM > To: php-general@lists.php.net > Subject: RE: [PHP] get image size function > > > > Here is the link to the site. > > http://shaggy.ohioprincipals.org/comgo_test/gallery.php > > Here is a link that shows the all of the code > > http://shaggy.ohioprincipals.org/comgo_test/gallery.html > > I have put as many of the variable values at the bottom of the > php page so > you can see what I am talking about. Thanks for all of the help. It's > greatly appreciated. > > > > > >From: "Jack Dempsey" <dempsejn@georgetown.edu> > >To: "Tyler Durdin" <linuxgeek23@hotmail.com>, > ><php-general@lists.php.net> > >Subject: RE: [PHP] get image size function > >Date: Wed, 9 Apr 2003 16:21:23 -0400 > > > >hey tyler, > > > > > When I echo/print the variables everything goes well until I get to > > > $photos = file($data_file); > > > > > > That's when I get a value of array. > > > Anybody got any idea why this is doing this? > > > >well, that's different than the line you listed before. > >$photos is obviously going to be an array because file() returns one: > > > >array file ( string filename [, int use_include_path]) > > > > > >as far as your errors before, if you would give the output of what i > >suggested, > >maybe we could figure things out...the url to the site to see if > the actual > >images are where > >php's looking could help too... > > > >jack > > > > > > > > > > > > > > > > > > > > > > > > >From: John Dempsey <dempsejn@gusun.georgetown.edu> > > > >To: Tyler Durdin <linuxgeek23@hotmail.com> > > > >CC: php-general@lists.php.net > > > >Subject: Re: [PHP] get image size function > > > >Date: Wed, 9 Apr 2003 15:38:47 -0400 (EDT) > > > > > > > >ok, so that looks like its not finding the file given in your photo > > > >array...not to doubt you, but are you sure you're getting the full > > > >filename, extension included, in the array, and that the file's > >actually > > > >in the same directory? try a test with file_exists to make sure > > > its there, > > > >and print out what the trim($photos[$i]) value is to double check > >what's > > > >happening... > > > > > > > >jack > > > > > > > >On Wed, 9 Apr 2003, Tyler Durdin wrote: > > > > > > > > > > > > > > > > > > > > > > > > > > > > > I ran the print_r and sure enough all of the image values > > > were there. So > > > >now > > > > > I am stuck again. This is the error message I am getting: > > > > > > > > > > Warning: getimagesize(Mvc-038f.jpg) > [function.getimagesize]: failed > >to > > > > > create stream: No such file or directory in > > > > > /www/servers/comgo_test/gallery.php on line 47 > > > > > > > > > > And this is line 47 > > > > > > > > > > $image_size = getimagesize(trim($photos[$i])); > > > > > > > > > > These are the variables the line is referring to > > > > > $photos = file($data_file); > > > > > ** the datafile just has the names of 3 jpg images ** > > > > > > > > > > > > > > > >From: dempsejn@georgetown.edu > > > > > >To: "Tyler Durdin" <linuxgeek23@hotmail.com> > > > > > >CC: php-general@lists.php.net > > > > > >Subject: Re: [PHP] get image size function > > > > > >Date: Wed, 09 Apr 2003 14:17:06 -0400 > > > > > > > > > > > >hey tyler, > > > > > > > > > > > >just looking at that quickly, i'd try testing it with print_r to > >see > > > > > >the structure; if you're getting the string "Array" then > > > > > >its > > > obviously > > > > > >an array that you have to then select something from. > print_r($var) > > > > > >should make it clear. > > > > > > > > > > > >jack > > > > > > > > > > > >----- Original Message ----- > > > > > >From: "Tyler Durdin" <linuxgeek23@hotmail.com> > > > > > >Date: Wednesday, April 9, 2003 2:13 pm > > > > > >Subject: [PHP] get image size function > > > > > > > > > > > > > When I run this script: > > > > > > > > > > > > > > <?php > > > > > > > $size = getimagesize ("pictures/pictures/bobby.jpg"); > > > > > > > echo "<img src=\"pictures/pictures/bobby.jpg\" > > > > > > > {$size[3]}>"; > > > > > > > ?> > > > > > > > > > > > > > > I get Array (the word Array) and a picture of the > image. Why am > >I > > > > > > > not > > > > > > > getting the image size? Did I not configure php to > use the image > > > > > > > functions? > > > > > > > If that's the case how can I correct this problem? If > it's not > >the > > > > > > > case what > > > > > > > is going on here? 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