RE: [PHP] get image size function

when you call getimagesize on the numbnail you do $thumbnail = $thumbnail_dir . trim($photos[$i]); however when you try to get the size of the photos you don't give it a directory, just the name. So, set a $picture_dir to wherever the pictures are, then $image = $picture_dir . trim($photos[$i]); $image_size = getimagesize($image); the same logic you used for the thumbnails jack > -----Original Message----- > From: Tyler Durdin [mailto:linuxgeek23@hotmail.com] > Sent: Wednesday, April 09, 2003 5:43 PM > To: php-general@lists.php.net > Subject: RE: [PHP] get image size function > > > So let me get this straight. I defined the thumbnail directory in > thumbnail_dir, but I never defined a directory for the photos? So > that would > mean that since it cannot find the photos the array would be > empty and just > display array, as it does for the $photos value. So, can you > recommend to me > where/how I should define the path the pictures? > Here's where I define the photos value: > $photos = file($data_file); > > the data file value is: > $data_file = "pictures/pictures/list.photos"; > > The $data_file lists the path, but for some reason the value of > $photos is > coming up as array (which i assume it's not finding it. Should I try > pointing it to the directory instead of to the text file? > > > > >ok, looking at that, i'd say a few things: > > > >first, its easier if you have .phps enabled, so the source is nice and > >colorized :-) > > > >also, on the lines that seem to work, you do: > > > >$thumbnail = $thumbnail_dir.trim($photos[$i]); > >$thumb_image_size = getimagesize($thumbnail); > >$image_size = getimagesize(trim($photos[$i])); > > > > > >having set $thumbnail_dir previously. > >but then you try to get the image of the photo without giving > the complete > >directory for it...try that and let me know... > > > > > >jack > > > > > -----Original Message----- > > > From: Tyler Durdin [mailto:linuxgeek23@hotmail.com] > > > Sent: Wednesday, April 09, 2003 4:37 PM > > > To: php-general@lists.php.net > > > Subject: RE: [PHP] get image size function > > > > > > > > > > > > Here is the link to the site. > > > > > > > > > http://shaggy.ohioprincipals.org/comgo_test/gallery.php > > > > > > Here is a link that shows the all of the code > > > > > > > > > http://shaggy.ohioprincipals.org/comgo_test/gallery.html > > > > > > I have put as many of the variable values at the bottom of the > > > php page so > > > you can see what I am talking about. Thanks for all of the help. It's > > > greatly appreciated. > > > > > > > > > > > > > > > >From: "Jack Dempsey" <dempsejn@georgetown.edu> > > > >To: "Tyler Durdin" <linuxgeek23@hotmail.com>, > ><php-general@lists.php.net> > > > >Subject: RE: [PHP] get image size function > > > >Date: Wed, 9 Apr 2003 16:21:23 -0400 > > > > > > > >hey tyler, > > > > > > > > > When I echo/print the variables everything goes well > until I get to > > > > > $photos = file($data_file); > > > > > > > > > > That's when I get a value of array. > > > > > Anybody got any idea why this is doing this? > > > > > > > >well, that's different than the line you listed before. > > > >$photos is obviously going to be an array because file() returns one: > > > > > > > >array file ( string filename [, int use_include_path]) > > > > > > > > > > > >as far as your errors before, if you would give the output of what i > > > >suggested, > > > >maybe we could figure things out...the url to the site to see if > > > the actual > > > >images are where > > > >php's looking could help too... > > > > > > > >jack > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > >From: John Dempsey <dempsejn@gusun.georgetown.edu> > > > > > >To: Tyler Durdin <linuxgeek23@hotmail.com> > > > > > >CC: php-general@lists.php.net > > > > > >Subject: Re: [PHP] get image size function > > > > > >Date: Wed, 9 Apr 2003 15:38:47 -0400 (EDT) > > > > > > > > > > > >ok, so that looks like its not finding the file given in > your photo > > > > > >array...not to doubt you, but are you sure you're > getting the full > > > > > >filename, extension included, in the array, and that the file's > > > >actually > > > > > >in the same directory? try a test with file_exists to make sure > > > > > its there, > > > > > >and print out what the trim($photos[$i]) value is to double check > > > >what's > > > > > >happening... > > > > > > > > > > > >jack > > > > > > > > > > > >On Wed, 9 Apr 2003, Tyler Durdin wrote: > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > I ran the print_r and sure enough all of the image values > > > > > were there. So > > > > > >now > > > > > > > I am stuck again. This is the error message I am getting: > > > > > > > > > > > > > > Warning: getimagesize(Mvc-038f.jpg) > > > [function.getimagesize]: failed > > > >to > > > > > > > create stream: No such file or directory in > > > > > > > /www/servers/comgo_test/gallery.php on line 47 > > > > > > > > > > > > > > And this is line 47 > > > > > > > > > > > > > > $image_size = getimagesize(trim($photos[$i])); > > > > > > > > > > > > > > These are the variables the line is referring to > > > > > > > $photos = file($data_file); > > > > > > > ** the datafile just has the names of 3 jpg images ** > > > > > > > > > > > > > > > > > > > > > >From: dempsejn@georgetown.edu > > > > > > > >To: "Tyler Durdin" <linuxgeek23@hotmail.com> > > > > > > > >CC: php-general@lists.php.net > > > > > > > >Subject: Re: [PHP] get image size function > > > > > > > >Date: Wed, 09 Apr 2003 14:17:06 -0400 > > > > > > > > > > > > > > > >hey tyler, > > > > > > > > > > > > > > > >just looking at that quickly, i'd try testing it > with print_r > >to > > > >see > > > > > > > >the structure; if you're getting the string > > > > > > > >"Array" then its > > > > > obviously > > > > > > > >an array that you have to then select something from. > > > print_r($var) > > > > > > > >should make it clear. > > > > > > > > > > > > > > > >jack > > > > > > > > > > > > > > > >----- Original Message ----- > > > > > > > >From: "Tyler Durdin" > > > > > > > ><linuxgeek23@hotmail.com> > > > > > > > >Date: Wednesday, April 9, 2003 2:13 pm > > > > > > > >Subject: [PHP] get image size function > > > > > > > > > > > > > > > > > When I run this script: > > > > > > > > > > > > > > > > > > <?php > > > > > > > > > $size = getimagesize > > > > > > > > > ("pictures/pictures/bobby.jpg"); > > > > > > > > > echo "<img > > > > > > > > > src=\"pictures/pictures/bobby.jpg\" > {$size[3]}>"; > > > > > > > > > ?> > > > > > > > > > > > > > > > > > > I get Array (the word Array) and a picture of the > > > image. Why am > > > >I > > > > > > > > > not > > > > > > > > > getting the image size? Did I not configure php to > > > use the image > > > > > > > > > functions? > > > > > > > > > If that's the case how can I correct this problem? > > > > > > > > > If > > > it's not > > > >the > > > > > > > > > case what > > > > > > > > > is going on here? Please help!!! > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > >_________________________________________________________________ > > > > > > > > > Protect your PC - get McAfee.com VirusScan Online > > > > > > > > > > > > > > > > > > http://clinic.mcafee.com/clinic/ibuy/campaign.asp?cid=3963 > > > > > > > > > > > > > > > > > > > > > > > > > > > -- > > > > > > > > > PHP General Mailing List (http://www.php.net/) > > > > > > > > > To unsubscribe, visit: > > > > > > > > > http://www.php.net/unsub.php > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > >-- > > > > > > > >PHP General Mailing List (http://www.php.net/) > > > > > > > >To unsubscribe, visit: > > > > > > > >http://www.php.net/unsub.php > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > >_________________________________________________________________ > > > > > > > MSN 8 helps eliminate e-mail viruses. 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