Re: Confused about return

Ok, I haven't looked at the Zend site, but just ignore the example you showed. <?php function foo( $x, $y ) { $a = $x + $y; $b = $x - $y; return array($a, $b); } $n = 5; $m = 2; $test = foo( $n , $m ); echo $test[0]; echo $test[1]; ?> This would output 7 and 3. I hope this example is a little clearer. -Rich "David VanHorn" <dvanhorn@cedar.net> wrote in message news:4.3.2.7.2.20000830105912.00de9580@mail.cedar.net... > > I'm confused over using the return function to return multiple values with > an array. > > From the Zend site, I get this example.. > > In a function, you can return multiple variables only by returning an array: > > function foo($x,$y) { > $a = $x+$y; > $b = $x-$y; > return array($a, $b, 1); > } > > list($sum, $sub) = foo(5, 2, 1); > > > > The way I read this, they are calling the function "foo" with three > variables, when it only needs/wants two., and I don't see where the output > of the "foo" function is ever presented... > > I would have expected something like > > $x=10; > $y=20; > foo($x,$y); > > followed by something that pulls up the returned values $a and $b, and the > passed static value of "1" > > Apparently, $sum becomes $x in the function, and $sub becomes $y, but the > rest of that line still confuses me, and I dont see how to get at the > passed result. > > BTW: If 5 is supposed to be $a and 2 is supposed to be $b, what the hell > was the input? > > 3.5 and 1.5 are the only pair I could come up with that satisfy that > equality, but where did they enter this example. > > Given that examples are supposed to make things clearer to people who don't > understand, I'd give this one, an F-. > > > > > -- > Where's dave? > http://www.findu.com/cgi-bin/find.cgi?kc6ete-9 > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >