Re: Show Filename using Wildcards

From: Date: Thu, 29 Mar 2007 19:53:30 +0000
Subject: Re: Show Filename using Wildcards
References: 1  Groups: php.general 
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Ave, This Works!! <?php exec("find /Users/rjohari/Documents/XFER/espi -type f -name ".$row['PHONE']."*.vox", $files); foreach ($files as $value) { echo substr($value,35)."<br>"; } ?> THANKS! ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Rahul Sitaram Johari CEO, Twenty Four Seventy Nine Inc. W: http://www.rahulsjohari.com E: sleepwalker@rahulsjohari.com ³I morti non sono piu soli ... The dead are no longer lonely² On 3/29/07 4:31 PM, "Peter Lauri" <lists@dwsasia.com> wrote: > [Peter Lauri - DWS Asia] > > Hi, > > Assuming you are on a linux you could try: > > exec("find /the/path/to/the/place/where/you/should/start/searching -type f > -name 515515515*.ext", $files); > > Then the $files will be an array with the found files matching the search.. > > Best regards, > Peter Lauri > > www.dwsasia.com - company web site > www.lauri.se - personal web site > www.carbonfree.org.uk - become Carbon Free > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php >

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