Re: Show Filename using Wildcards

Awesome!! This Works!! <?php exec("find /Users/rjohari/Documents/XFER/espi -type f -name ".$row['PHONE']."*.vox", $files); foreach ($files as $value) { echo basename($value)."<br>"; } ?> THANKS! ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Rahul Sitaram Johari CEO, Twenty Four Seventy Nine Inc. W: http://www.rahulsjohari.com E: sleepwalker@rahulsjohari.com “I morti non sono piu soli ... The dead are no longer lonely” On 3/29/07 3:52 PM, "Ben Roberts" <list-support@headsnet.com> wrote: > Rahul Sitaram Johari wrote: > >> So I have to accomplish two things: >> >> 1. I have to eliminate the filepath from the result >> 2. I need to specify the variable that holds the phone number, (like >> $row[ŒPHONE¹]) instead of the actual phone number in the ³exec² command. >> >> Thanks!! Much Appreciated! >> > > To get the filename component without the path, just use the basename() > function: > > $file = basename($path); > > Ben