Re: Show Filename using Wildcards
| From: | Tijnema ! | Date: | Thu, 29 Mar 2007 19:58:24 +0000 |
| Subject: | Re: Show Filename using Wildcards | ||
| References: | 1 2 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-251676@lists.php.net to get a copy of this message | ||
On 3/29/07, Rahul Sitaram Johari <sleepwalker@rahulsjohari.com> wrote:
Ave, This Works!! <?php exec("find /Users/rjohari/Documents/XFER/espi -type f -name ".$row['PHONE']."*.vox", $files); foreach ($files as $value) {I recommend using basename($value) instead of substr($value,35) If the directory changes, the basename would still return valid values, while substr wouldn't Tijnemaecho substr($value,35)."<br>";} ?> THANKS!
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Rahul Sitaram Johari CEO, Twenty Four Seventy Nine Inc. W: http://www.rahulsjohari.com E: sleepwalker@rahulsjohari.com ³I morti non sono piu soli ... The dead are no longer lonely² On 3/29/07 4:31 PM, "Peter Lauri" <lists@dwsasia.com> wrote: [Peter Lauri - DWS Asia] Hi, Assuming you are on a linux you could try: exec("find /the/path/to/the/place/where/you/should/start/searching -type f -name 515515515*.ext", $files); Then the $files will be an array with the found files matching the search. Best regards, Peter Lauri www.dwsasia.com - company web site www.lauri.se - personal web site www.carbonfree.org.uk - become Carbon Free -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php