Re: Finding next recored in a array

Jim Lucas wrote:

Richard Kurth wrote:

$query = "    SELECT    day
        FROM    emailcampaign
        where    campaign_id = '$emailcampaign'
        AND    member_id = '$members_id'
    ";

$DB_Change_Campaign_Results = safe_query($query); while ( $row = mysql_fetch_array($DB_Change_Campaign_Results) ) {

    $Campaign_array[$row['day']] = $row;

} # At this point you have arrays as values for your $Campaign_array # So, unless $k is an array that matches a sub array of $Campaign_array # you're never going to get a match $k = array_search($val,$Campaign_array); # What is $k at this point? An int (1, 2, 3, etc...) , string (Sunday, Monday, etc...) # Before I go any further I will need to know the above information. if ( ($k + 1) < count($Campaign_array) ) {

    echo $Campaign_array[$k + 1];

} This is what I get if I run the above script.

From a var_dump($Campaign_array); I get *array* 0 => *array*

     0 => string '0' /(length=1)/
     'day' => string '0' /(length=1)/
 1 =>    *array*
     0 => string '1' /(length=1)/
     'day' => string '1' /(length=1)/
 3 =>    *array*
     0 => string '3' /(length=1)/
     'day' => string '3' /(length=1)/
 6 =>    *array*
     0 => string '6' /(length=1)/
     'day' => string '6' /(length=1)/
 9 =>    *array*
     0 => string '9' /(length=1)/
     'day' => string '9' /(length=1)/
 12 =>    *array*
     0 => string '12' /(length=2)/
     'day' => string '12' /(length=2)/
 15 =>    *array*
     0 => string '15' /(length=2)/
     'day' => string '15' /(length=2)/
 20 =>    *array*
     0 => string '20' /(length=2)/
     'day' => string '20' /(length=2)/
 25 =>    *array*
     0 => string '25' /(length=2)/
     'day' => string '25' /(length=2)/
 30 => 

*array*

     0 => string '30' /(length=2)/
     'day' => string '30' /(length=2)/

From a $val="5"; $k = array_search($val,$Campaign_array); var_dump($k); I get boolean false