Re: Finding next recored in a array

From: Date: Mon, 17 Sep 2007 19:51:56 +0000
Subject: Re: Finding next recored in a array
References: 1 2 3 4 5 6 7 8 9 10  Groups: php.general 
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REVISED Try this <?php $query = " SELECT day FROM emailcampaign WHERE campaign_id = '$emailcampaign' AND member_id = '$members_id' "; $DB_Change_Campaign_Results = safe_query($query); ## ## NOTICE: changed from array to assoc ## $Campaign_array = array(); while ( $row = mysql_fetch_assoc($DB_Change_Campaign_Results) ) { ## Switched to an indexed array with the day as the value instead of the key $Campaign_array[] = $row['day']; } # At this point you have arrays as values for your $Campaign_array # So, unless $k is an array that matches a sub array of $Campaign_array # you're never going to get a match $k = array_search($val,$Campaign_array); # What is $k at this point? An int (1, 2, 3, etc...) , string (Sunday, Monday, etc...) # Before I go any further I will need to know the above information. if ( isset($Campaign_array[($k + 1)])) { echo $Campaign_array[($k + 1)]; } else { echo 'Not found'; } -- Jim Lucas "Some men are born to greatness, some achieve greatness, and some have greatness thrust upon them." Twelfth Night, Act II, Scene V by William Shakespeare

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