Re: Finding next recored in a array
| From: | tedd | Date: | Thu, 20 Sep 2007 19:56:21 +0000 |
| Subject: | Re: Finding next recored in a array | ||
| References: | 1 2 3 4 5 6 7 8 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-262312@lists.php.net to get a copy of this message | ||
At 4:14 PM -0400 9/19/07, brian wrote:
tedd wrote:~sigh~ Sorry to disappoint you master. But I was using array_search() to search an array -- it seemed like a reasonable thing to do. So why do you say it's an example of what *not* to do with array_search()? Please be specific. Cheers, tedd -- ------- http://sperling.com http://ancientstones.com http://earthstones.comAt 11:52 AM -0400 9/17/07, brian wrote:~sigh~ Grasshopper, the point i was trying to make is that your example displays what *not* to do with array_search(). Though a wonderful teaching aid in itself, it falls somewhat short of being a reasonable solution for the OP. briantedd wrote:Duh? You program for that -- you want me to write the entire code?Richard Kurth wrote:Not quite: $array = array('0','1','3','5','8','15','25'); $val = "25"; echo($array[array_search($val, $array)+1]); Notice: Undefined offset: 7 ... brian$Campaign_array| = array('0','1','3','5','8','15','25');| I know that I can find the next recored in a array using next. What I do not understand is if I know the last number was say 5 how do I tell the script that that is the current number so I can select the next recordWhat the next record? Try:$array = array('0','1','3','5','8','15','25'); $val = "5";echo($array[array_search($val, $array)+1]);Cheers, tedd