Re: PHP and MySQL SELECT COUNT (*)

""Dan Joseph"" <dmjoseph@gmail.com> wrote in message news:a20394490809171140u436b0d40yad003e31592a70f9@mail.gmail.com...

On Wed, Sep 17, 2008 at 2:30 PM, Vinny Gullotta <vgullotta@intermedia.net>wrote:

""Dan Joseph"" <dmjoseph@gmail.com> wrote in message news:a20394490809171120o63691c31idc356aeae78681f3@mail.gmail.com... On Wed, Sep 17, 2008 at 2:17 PM, Vinny Gullotta <vgullotta@intermedia.net

wrote:

What I want to do is find the top 10 servers where the column steps =

iisreset. The following code works great except that the page is not displaying the servername in the 'Server Name' column of my results (nothing appears, the column is just blank). servername and steps are the important columns in the database table. $_POST[time1] and $_POST[time2] come from a form submitted. When I copy and paste the entire select statement into the SQL tab in phpmyadmin (and replace the time variables with actual times corresponding to the timestamp column), it displays the correct results including servername. Everything works in the php page's results except for the servername. I feel like it's right in front of my face and that's why I can't see it lol. Any help would be greatly appreciated. Thanks in advance =) My code... $query = "SELECT servername, COUNT(steps) FROM monitoring WHERE steps LIKE 'iisreset' AND timestamp <= '$_POST[time2]' AND timestamp >= '$_POST[time1]' GROUP BY servername ORDER BY COUNT(*) DESC LIMIT 10"; $result = mysql_query($query) or die(mysql_error()); # display column titles echo "<center><table class='table'><tr>"; echo "<td class='tableHeader'><center><small><b>Count</b></small></td>"; echo "<td class='tableHeader'><center><small><b>Server Name</b></small></td>"; echo "</tr>"; #display results while($i = mysql_fetch_row($result)) { echo "<tr><td><small><center>", $i[COUNT('steps')], "</center></small></td>"; echo "<td><small><center>", $i[servername] ,"</center></small></td></tr>"; } echo "</table></center><br>"; -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Change that "COUNT(steps)" to "COUNT(steps) AS CountSteps", that might

be the issue. Then you're using $i['CountSteps']. That seems a bit more normal looking to me atleast. Also, try echoing out your query on the screen to see that its formating properly in the PHP code. You may have something wrong in there, although I don't see any off hand. -- -Dan Joseph www.canishosting.com - Plans start @ $1.99/month. "Build a man a fire, and he will be warm for the rest of the day. Light a man on fire, and will be warm for the rest of his life."

Adding as CountSteps $i['CountSteps'] still leaves the column blank. echo $result; gives me an output of: Resource id #3 and echo $query; just gives me an error. One thing I don't understand is why echo $result; gives me Resource id #3 as an output. What does that mean? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php

That's basically your result set ID number inside PHP. as for $query, what error are you getting? Does this $query echo out: $query = "SELECT servername, COUNT(steps) AS CountSteps FROM monitoring WHERE steps LIKE 'iisreset' AND timestamp <= '" . $_POST['time2'] . "' AND timestamp >= '" . $_POST['time1'] . "' GROUP BY servername ORDER BY COUNT(*) DESC LIMIT 10"; -- -Dan Joseph www.canishosting.com - Plans start @ $1.99/month. "Build a man a fire, and he will be warm for the rest of the day. Light a man on fire, and will be warm for the rest of his life."

It's actually not an error, it's the select statement that is echo'd echo $query; yields SELECT servername, COUNT(steps) as CountSteps FROM monitoring WHERE steps = 'IISRESET' AND timestamp <= '2008-09-17 11:40:34' AND timestamp >= '2008-08-17' GROUP BY servername ORDER BY COUNT(*) DESC LIMIT 10