Re: PHP and MySQL SELECT COUNT (*)

I meant key in the array that was returned by MySQL. I answered you in my other post. The array was numerically index based instead of column based. Thank you, Micah Gersten onShore Networks Internal Developer http://www.onshore.com Vinny Gullotta wrote: > If by key you mean the column in the database, it's called: servername > > "Micah Gersten" <micah@onshore.com> wrote in message > news:48D16738.7040504@onshore.com... >> What is the key for the server name? That's what you need when you >> output it. >> >> Thank you, >> Micah Gersten >> onShore Networks >> Internal Developer >> http://www.onshore.com >> >> >> >> Vinny Gullotta wrote: >>> var_dump($i); looks messy, but I can see the server names in there and >>> they are the correct names. >>> >>> >>> "Micah Gersten" <micah@onshore.com> wrote in message >>> news:48D1629D.3040801@onshore.com... >>>> Do var_dump($i) in the loop to see if you're getting the data you >>>> want. >>>> >>>> Thank you, >>>> Micah Gersten >>>> onShore Networks >>>> Internal Developer >>>> http://www.onshore.com >>>> >>>> >>>> >>>> Vinny Gullotta wrote: >>>>> Still no luck displaying the stupid servername. Any other things I >>>>> can >>>>> try? >>>>> >>>>> >>>>> "Micah Gersten" <micah@onshore.com> wrote in message >>>>> news:48D15B41.8010208@onshore.com... >>>>>> You'll want to change your Order By statement to 'ORDER BY >>>>>> CountSteps >>>>>> DESC'. >>>>>> >>>>>> Thank you, >>>>>> Micah Gersten >>>>>> onShore Networks >>>>>> Internal Developer >>>>>> http://www.onshore.com >>>>>> >>>>>> >>>>>> >>>>>> Vinny Gullotta wrote: >>>>>>> echo $query; >>>>>>> >>>>>>> yields >>>>>>> >>>>>>> SELECT servername, COUNT(steps) as CountSteps FROM monitoring WHERE >>>>>>> steps = 'IISRESET' AND timestamp <= '2008-09-17 >>>>>>> 11:40:34' AND >>>>>>> timestamp >= '2008-08-17' GROUP BY servername ORDER BY >>>>>>> COUNT(*) >>>>>>> DESC >>>>>>> LIMIT 10 >>>>>>> >>>>> >>>>> >>> >>> > >