Re: PHP and MySQL SELECT COUNT (*)

From: Date: Wed, 17 Sep 2008 20:30:59 +0000
Subject: Re: PHP and MySQL SELECT COUNT (*)
References: 1 2 3 4 5 6 7 8 9 10  Groups: php.general 
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If by key you mean the column in the database, it's called: servername "Micah Gersten" <micah@onshore.com> wrote in message news:48D16738.7040504@onshore.com...
What is the key for the server name? That's what you need when you output it. Thank you, Micah Gersten onShore Networks Internal Developer http://www.onshore.com Vinny Gullotta wrote:
var_dump($i); looks messy, but I can see the server names in there and they are the correct names. "Micah Gersten" <micah@onshore.com> wrote in message news:48D1629D.3040801@onshore.com...
Do var_dump($i) in the loop to see if you're getting the data you want. Thank you, Micah Gersten onShore Networks Internal Developer http://www.onshore.com Vinny Gullotta wrote:
Still no luck displaying the stupid servername. Any other things I can try? "Micah Gersten" <micah@onshore.com> wrote in message news:48D15B41.8010208@onshore.com...
You'll want to change your Order By statement to 'ORDER BY CountSteps DESC'. Thank you, Micah Gersten onShore Networks Internal Developer http://www.onshore.com Vinny Gullotta wrote:
echo $query; yields SELECT servername, COUNT(steps) as CountSteps FROM monitoring WHERE steps = 'IISRESET' AND timestamp <= '2008-09-17 11:40:34' AND timestamp >= '2008-08-17' GROUP BY servername ORDER BY COUNT(*) DESC LIMIT 10


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