fgetcsv doesn't return an array?

From: Date: Thu, 15 Mar 2012 17:09:53 +0000
Subject: fgetcsv doesn't return an array?
Groups: php.general 
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I thought that fgetcsv returned an array. I can work with it like an array but I get the following warning when using it |Warning: implode(): Invalid arguments passed on line 155 154 $csvCurrentLine = fgetcsv($csvFile, 4096, ','); 155 $currentLine = implode(",", $csvCurrentLine); | Everything that I have read online indicates that it is because $csvCurrentLine is not declared as an array. Adding a line to the code 153 |$csvCurrentLine = array(); Does not get rid of the warning. The warning isn't interfering with the script working, but it us annoying. Does anyone know the solution? Thanks! Jay |

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