Re: fgetcsv doesn't return an array?

On 03/15/2012 10:09 AM, Jay Blanchard wrote:

I thought that fgetcsv returned an array. I can work with it like an array but I get the following warning when using it |Warning: implode(): Invalid arguments passed on line 155 154 $csvCurrentLine = fgetcsv($csvFile, 4096, ','); 155 $currentLine = implode(",", $csvCurrentLine); | Everything that I have read online indicates that it is because $csvCurrentLine is not declared as an array. Adding a line to the code 153 |$csvCurrentLine = array(); Does not get rid of the warning. The warning isn't interfering with the script working, but it us annoying. Does anyone know the solution? Thanks! Jay |

From the manual "fgetcsv() returns NULL if an invalid handle is supplied or FALSE on other errors, including end of file." do this 154 $csvCurrentLine = fgetcsv($csvFile, 4096, ','); var_dump($csvCurrentLine); 155 $currentLine = implode(",", $csvCurrentLine); What does it say about the variable from the failing line? -- Jim Lucas http://www.cmsws.com/ http://www.cmsws.com/examples/ http://www.bendsource.com/