Re: fgetcsv doesn't return an array?
| From: | Jay Blanchard | Date: | Thu, 15 Mar 2012 17:29:23 +0000 |
| Subject: | Re: fgetcsv doesn't return an array? | ||
| References: | 1 2 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-317029@lists.php.net to get a copy of this message | ||
On 3/15/2012 12:23 PM, Matijn Woudt wrote:
On Thu, Mar 15, 2012 at 6:09 PM, Jay Blanchard <jay.blanchard@sigmaphinothing.org> wrote:I thought that fgetcsv returned an array. I can work with it like an array but I get the following warning when using it |Warning: implode(): Invalid arguments passed on line 155Are you using this in a loop or something? fgetcsv returns FALSE on errors, including End Of File. [/snip] I am using it in a loop. End Of File is an error?154 $csvCurrentLine = fgetcsv($csvFile, 4096, ','); 155 $currentLine = implode(",", $csvCurrentLine);| Everything that I have read online indicates that it is because $csvCurrentLine is not declared as an array. Adding a line to the code 153 |$csvCurrentLine = array(); Does not get rid of the warning. The warning isn't interfering with the script working, but it us annoying. Does anyone know the solution? Thanks! Jay |