Re: Passing variables with include()
| From: | Martin Wickman | Date: | Mon, 14 Jan 2002 13:40:29 +0000 |
| Subject: | Re: Passing variables with include() | ||
| References: | 1 2 3 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-80452@lists.php.net to get a copy of this message | ||
Imar De Vries wrote:
Imar De Vries wrote:Not really. The http://.../foo.php request returns html and not php. The foo.php file is parsed and executed by the remote server and returned to you as html. By adding serie_id=xxx you actually give the remote php-script the name and value of the variable. You should think of include/require as a way to *include* any file into your script. Instead of cutting and pasting code into your file, you use include. Thats the way it works in practice. No magic is going on here :-)- Including remote files *is* possible. The php manual does not mention this does not work, and when I add the variable to the call (include ..../calculate_drivers?serie_id=3.php) the code is processed perfectly. The thing is, I can not pass the variable with the call, because it's value is determined by the form field. I could use a switch statement of course, but that adds a lot more text to the code.I just changed the code to (include .../calculate_drivers?serie_id=$serie_id.php) ... and this worked! Weird solution...