Re: Pass source object to clone like __clone($origThis)
| From: | David Rodrigues | Date: | Wed, 02 Sep 2020 19:10:55 +0000 |
| Subject: | Re: Pass source object to clone like __clone($origThis) | ||
| References: | 1 | Groups: | php.internals |
| Request: | Send a blank email to internals+get-111793@lists.php.net to get a copy of this message | ||
I understand... seems that
$this is very confusing inside __clone():
when writing, it writes to the clone, when reading it reads from original.
Seems valid a new optional parameter definition with the original source.
Atenciosamente,
David Rodrigues
Em qua., 2 de set. de 2020 à s 15:41, Michael VoÅ™ÃÅ¡ek - ÄŒVUT FEL <
vorismi3@fel.cvut.cz> escreveu:
> Hi, please look at
>
>
> https://stackoverflow.com/questions/63675888/get-original-source-instance-in-cloneµú
> Xl,S@çG{XàÁŠ
>
>
> do you have anything against updating PHP to pass "instance before
> cloned" to any __clone call from php?
>
> no BC - user may accept this extra argument or declare function
> __clone() without any param like now
>
> With kind regards / Mit freundlichen Grüßen / S přátelským pozdravem,
>
> Michael VoÅ™ÃÅ¡ek