Re: Pass source object to clone like __clone($origThis)

On Wed, Sep 2, 2020 at 2:11 PM David Rodrigues <david.proweb@gmail.com> wrote: > I understand... seems that $this is very confusing inside > __clone(): > when writing, it writes to the clone, when reading it reads from original. > > That's not an accurate description of what happens today. $newObj = clone $oldObj; // 1. Engine creates a new instance of get_class($oldObj), without calling the constructor // 2. Engine copies all properties from the old object to the new object // 3. Engine invokes $newObj->__clone() public function __clone() { // Userspace object handles any property specific re-initialization required. // $this always refers to the new object here. } The question Niki asked is appropriate; What would one want to do to $oldObj here? If the goal is to read from the old object, then you have that already. The new object is a perfect copy, so read from that. If the goal is to write to the old object, then justify why you need to do so, because it's not a clone operation at that point. -Sara