Re: Pass source object to clone like __clone($origThis)

It was just an example to avoid modify how clone works, using existing features. :) Em qui, 3 de set de 2020 13:00, Sara Golemon <pollita@php.net> escreveu: > On Thu, Sep 3, 2020 at 10:40 AM David Rodrigues <david.proweb@gmail.com> > wrote: > >> Now I rethinked about what I said. Really, maybe clone is not the best >> option. So maybe we can just use a method that will clone and will have >> access to both informations. But I don't know if it solves the original >> message. >> >> public function getUserCopy() { >> $userCopy = clone $this; >> $this->copies[] = $userCopy; >> >> return $userCopy; >> } >> >> > If your goal is to track copies, then a static makes much more sense. > > class AllKnowing { > private static $copies = []; > > public function __construct(...) { > self::$copies[] = $this; > .... > } > > public function __clone() { > self::$copies[] = $this; > } > } > > -Sara >