Re: Implicit isset in ternary operator

> I think that you can compare the situation to the short if syntax ($a > $b > ? $c : $d) Not sure I understand... that *is* the situation under discussion, no? $a > $b ? ... and $a ? ... both use the ternary operator. You do raise (maybe on purpose, not totally clear what you were getting at) the question of whether a more complex (expr1) in one of these theoretical ternarys w/implicit isset, however it is implemented, would apply the isset to _any_ variable in (expr1)? That is, if $a or $b do not exist, does $a > $b ?? ... return an error? What if both do not exist? I think the conclusion (as reached by other people) is that the operator needs to apply to each individual variable, not to a multi-step deal like the ternary where there are more cases to consider. -- S.