Re: [PHP4BETA] A quick clarification question about PHP4...

From: Date: Thu, 26 Aug 1999 06:29:08 +0000
Subject: Re: [PHP4BETA] A quick clarification question about PHP4...
References: 1 2  Groups: php.version4 
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I wrote a recordset database class (for Informix) along these new guidelines, where all variables are initialized in the constructors (without $var) as a way of documenting them. The recordset constructor takes a database class reference as an argument, and it works in PHP3 and PHP4. See http://users.pandora.be/danny.heijl/rs.zip . Danny. --- ----- Original Message ----- From: "Samuel Liddicott" <sam@campbellsci.co.uk> Newsgroups: php4.beta Sent: woensdag 25 augustus 1999 14:22 Subject: RE: [PHP4BETA] A quick clarification question about PHP4... > > > > -----Original Message----- > > From: Andi Gutmans [mailto:andi@zend.com] > > Sent: 25 August 1999 01:17 PM > > To: Samuel Liddicott; zeev@zend.com; Jim Brain; Zend > > Subject: RE: [PHP4BETA] A quick clarification question about PHP4... > > > > At 11:25 AM 8/25/99 +0100, Samuel Liddicott wrote: > > > > >Wow. I use it as self-documentation otherwise I can never remember the > > >names of variables and end up with buggy code because I have two > > different > > >spellings. Oh well. > > > > You could have used comments for that :) > > # var $foo; > > :-) > I'm prone to comments getting out of date... > > > > > It's not the C++ model, it's a typical compile&execute model. > > > > > >Well it's not very nice... > > > > > >Also I move that constructors allow parameters. > > > > They do. > > Oh. I must have been confused during a sock in the recent fight. > > Does > > $item=new thingy(1,2); > > work then? How do you pass the parameters during construction? > > Sam > > -- > PHP 4 Beta >

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