Re: Query question
| From: | Joe Wollard | Date: | Sun, 29 Oct 2006 02:30:14 +0000 |
| Subject: | Re: Query question | ||
| References: | 1 2 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-243812@lists.php.net to get a copy of this message | ||
Agreed, this should go to a MySQL list. But in the spirit of helping I think
the following should give you a good starting point.
SELECT
year, COUNT(year) AS count FROM tbl GROUP BY year ASC
On 10/28/06, Ed Lazor <edlazor@yahoo.com> wrote:
Use the mysql list :) On Oct 28, 2006, at 3:01 PM, Beauford wrote: Hi, I have a MySQL database with a date field and a bunch of other fields. The date field is in the format - 01/01/2006. What I want to do is query the database and create a table that shows just the year and how many instances of the year there is. I have been taxing my brain for a simple solution, but just not getting it. Any suggestions? Thanks Example output. Year Count 2002 5 2003 8 2004 9 2005 15 2006 22 ps - I get this information sent to me and I can't change any of the data. I just enter it in the db and then hopefully do the query on it. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php