Re: Query question

From: Date: Sun, 29 Oct 2006 04:14:50 +0000
Subject: Re: Query question
References: 1 2  Groups: php.general 
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Look into the MySQL YEAR() function to extract the year from a specific date. Start here: http://dev.mysql.com/doc/refman/5.0/en/date-and-time-functions.html On 10/28/06, Beauford <php-user@netscan.ca> wrote:
I posted this here as I figured I would need to manipulate this using PHP. The code below doesn't quite work because the date is in the format of 05/05/2006. So I am getting totals for each date, not each year. I need the totals for each year, regardless of the day or month. This is why I figured I'd need to use PHP to maybe put it in an array first or something. Thanks -----Original Message----- From: Joe Wollard [mailto:joe.wollard@gmail.com] Sent: October 28, 2006 10:30 PM To: Ed Lazor Cc: Beauford; PHP Subject: Re: [PHP] Query question Agreed, this should go to a MySQL list. But in the spirit of helping I think the following should give you a good starting point. SELECT year, COUNT(year) AS count FROM tbl GROUP BY year ASC On 10/28/06, Ed Lazor <edlazor@yahoo.com> wrote: Use the mysql list :) On Oct 28, 2006, at 3:01 PM, Beauford wrote:
Hi, I have a MySQL database with a date field and a bunch of other fields. The date field is in the format - 01/01/2006. What I want to do is query the database and create a table that shows just the year and how many instances of the year there is. I have been taxing my brain for a simple solution, but just not getting it. Any suggestions? Thanks Example output. Year Count 2002 5 2003 8 2004 9 2005 15 2006 22 ps - I get this information sent to me and I can't change any of the data. I just enter it in the db and then hopefully do the query on it.
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