RE: [PHP] Query question
| From: | Beauford | Date: | Sun, 29 Oct 2006 06:05:26 +0000 |
| Subject: | RE: [PHP] Query question | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-243816@lists.php.net to get a copy of this message | ||
This is what I finally figured out, which works just perfectly.
select count(date) as count, substring(date,8) as year from stats group by
year;
Thanks to all for the input.
-----Original Message-----
From: Joe Wollard [mailto:joe.wollard@gmail.com]
Sent: October 29, 2006 12:15 AM
To: Beauford
Cc: PHP
Subject: Re: [PHP] Query question
Look into the MySQL YEAR() function to extract the year from a specific
date.
Start here:
http://dev.mysql.com/doc/refman/5.0/en/date-and-time-functions.html
On 10/28/06, Beauford <php-user@netscan.ca> wrote:
>
> I posted this here as I figured I would need to manipulate this using PHP.
> The code below doesn't quite work because the date is in the format of
> 05/05/2006. So I am getting totals for each date, not each year. I
> need the totals for each year, regardless of the day or month. This is
> why I figured I'd need to use PHP to maybe put it in an array first or
> something.
>
> Thanks
>
> -----Original Message-----
> From: Joe Wollard [mailto:joe.wollard@gmail.com]
> Sent: October 28, 2006 10:30 PM
> To: Ed Lazor
> Cc: Beauford; PHP
> Subject: Re: [PHP] Query question
>
> Agreed, this should go to a MySQL list. But in the spirit of helping I
> think the following should give you a good starting point.
>
> SELECT
year, COUNT(year) AS
> count FROM tbl GROUP BY
> year ASC
>
>
> On 10/28/06, Ed Lazor <edlazor@yahoo.com> wrote:
> >
> > Use the mysql list :)
> >
> >
> > On Oct 28, 2006, at 3:01 PM, Beauford wrote:
> >
> > > Hi,
> > >
> > > I have a MySQL database with a date field and a bunch of other
> > > fields. The date field is in the format - 01/01/2006. What I want
> > > to do is query the database and create a table that shows just the
> > > year and how many instances of the year there is. I have been
> > > taxing my brain for a simple solution, but just not getting it.
> > > Any suggestions?
> > >
> > > Thanks
> > >
> > > Example output.
> > >
> > > Year Count
> > >
> > > 2002 5
> > > 2003 8
> > > 2004 9
> > > 2005 15
> > > 2006 22
> > >
> > > ps - I get this information sent to me and I can't change any of
> > > the data. I just enter it in the db and then hopefully do the
> > > query on it.
> > >
> > >
> >
> > --
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> >
> >
>
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