RE: [PHP] Query question
| From: | Beauford | Date: | Sun, 29 Oct 2006 03:21:15 +0000 |
| Subject: | RE: [PHP] Query question | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-243813@lists.php.net to get a copy of this message | ||
I posted this here as I figured I would need to manipulate this using PHP.
The code below doesn't quite work because the date is in the format of
05/05/2006. So I am getting totals for each date, not each year. I need the
totals for each year, regardless of the day or month. This is why I figured
I'd need to use PHP to maybe put it in an array first or something.
Thanks
-----Original Message-----
From: Joe Wollard [mailto:joe.wollard@gmail.com]
Sent: October 28, 2006 10:30 PM
To: Ed Lazor
Cc: Beauford; PHP
Subject: Re: [PHP] Query question
Agreed, this should go to a MySQL list. But in the spirit of helping I think
the following should give you a good starting point.
SELECT
year, COUNT(year) AS count FROM tbl GROUP
BY year ASC
On 10/28/06, Ed Lazor <edlazor@yahoo.com> wrote:
>
> Use the mysql list :)
>
>
> On Oct 28, 2006, at 3:01 PM, Beauford wrote:
>
> > Hi,
> >
> > I have a MySQL database with a date field and a bunch of other
> > fields. The date field is in the format - 01/01/2006. What I want to
> > do is query the database and create a table that shows just the year
> > and how many instances of the year there is. I have been taxing my
> > brain for a simple solution, but just not getting it. Any
> > suggestions?
> >
> > Thanks
> >
> > Example output.
> >
> > Year Count
> >
> > 2002 5
> > 2003 8
> > 2004 9
> > 2005 15
> > 2006 22
> >
> > ps - I get this information sent to me and I can't change any of the
> > data. I just enter it in the db and then hopefully do the query on
> > it.
> >
> >
>
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