Re: Return an Array and immediately reference an index

Top-posting side comment: It's not nice to hijack threads. My comments are below... On Apr 11, 2008, at 5:33 PM, Daniel Kolbo wrote:

Hello, I want to return an array from function and reference an index all in one line. Is this possible? In the code below I want I want $yo to be the array(5,6). Here is what I've tried, function returnarray() { return array('lose' => array(5,6), 'win' => array(9,8)); } $yo = returnarray()['lose']; var_dump($yo); This yields a parse error. function returnarray() { return array('lose' => array(5,6), 'win' => array(9,8)); } $yo = {returnarray()}['lose']; var_dump($yo); This yields a parse error. function returnarray() { return array('lose' => array(5,6), 'win' => array(9,8)); } $yo = ${returnarray()}['lose']; var_dump($yo); This gives notices as the result of returnarray() is being converted to a string. $yo === NULL...not what i want. function returnarray() { return array('lose' => array(5,6), 'win' => array(9,8)); } $yo = returnarray()->['lose']; var_dump($yo); This yields a parse error. function returnarray() { return array('lose' => array(5,6), 'win' => array(9,8)); } $yo = ${returnarray()}->['lose']; var_dump($yo); This yields a parse error. Thanks for your help in advance.

Perhaps these pages may assist you: http://php.net/manual/en/function.array.php http://php.net/functions For more immediate help, I think you want to do something along these lines: <?php function returnArray ($index) {

    $arr = array('lose'=>array(5,6), 'win'=>array(9,8));
    return isset ($arr[$index]) ? $arr[$index] : 'Index not found';

} $returnTheValueForThis = 'lose'; $result = returnArray ($returnTheValueForThis); var_dump ($result); ?> This var_dump will return: array(2) { [0]=> int(5) [1]=> int(6) } Hope that helps. Do some more reading in the manual to help yourself out. ;) ~Philip