Re: Return an Array and immediately reference an index
| From: | Daniel Kolbo | Date: | Fri, 11 Apr 2008 23:31:17 +0000 |
| Subject: | Re: Return an Array and immediately reference an index | ||
| References: | 1 2 3 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-272900@lists.php.net to get a copy of this message | ||
Philip Thompson wrote:
Top-posting side comment: It's not nice to hijack threads. My comments are below... On Apr 11, 2008, at 5:33 PM, Daniel Kolbo wrote:Just to be sure, where you saying I hijacked a thread? If so, please educate me as to how i did this. Now to the response. Thanks for the response. I am familiar with the construction and returning of the arrays and referencing an index of the array. I understand your code. However, this is not what I am trying to do. I could simply do: function returnarray() {Hello, I want to return an array from function and reference an index all in one line. Is this possible? In the code below I want I want $yo to be the array(5,6). Here is what I've tried, function returnarray() {Perhaps these pages may assist you: http://php.net/manual/en/function.array.php http://php.net/functions For more immediate help, I think you want to do something along these lines: <?php function returnArray ($index) {return array('lose' => array(5,6), 'win' => array(9,8));} $yo = returnarray()['lose']; var_dump($yo); This yields a parse error. function returnarray() {return array('lose' => array(5,6), 'win' => array(9,8));} $yo = {returnarray()}['lose']; var_dump($yo); This yields a parse error. function returnarray() {return array('lose' => array(5,6), 'win' => array(9,8));} $yo = ${returnarray()}['lose']; var_dump($yo); This gives notices as the result of returnarray() is being converted to a string. $yo === NULL...not what i want. function returnarray() {return array('lose' => array(5,6), 'win' => array(9,8));} $yo = returnarray()->['lose']; var_dump($yo); This yields a parse error. function returnarray() {return array('lose' => array(5,6), 'win' => array(9,8));} $yo = ${returnarray()}->['lose']; var_dump($yo); This yields a parse error. Thanks for your help in advance.$arr = array('lose'=>array(5,6), 'win'=>array(9,8)); return isset ($arr[$index]) ? $arr[$index] : 'Index not found';} $returnTheValueForThis = 'lose'; $result = returnArray ($returnTheValueForThis); var_dump ($result); ?> This var_dump will return: array(2) { [0]=> int(5) [1]=> int(6) } Hope that helps. Do some more reading in the manual to help yourself out. ;) ~Philip
return array('lose' => array(5,6), 'win' => array(9,8));
}
$yo = returnarray();
var_dump($yo['lose']);
To get my desired result.
I was just seeing if PHP had the capability to combine those last two lines into one. I realize the function itself is rather trivial, but just wanted some function to return an array for the sake of demonstration.
Thanks,