Re: Return an Array and immediately reference an index

On Apr 12, 2008, at 12:33 AM, Daniel Kolbo wrote:

Hello, I want to return an array from function and reference an index all in one line. Is this possible? In the code below I want I want $yo to be the array(5,6). Here is what I've tried, function returnarray() { return array('lose' => array(5,6), 'win' => array(9,8)); } $yo = returnarray()['lose']; var_dump($yo); This yields a parse error. function returnarray() { return array('lose' => array(5,6), 'win' => array(9,8)); } $yo = {returnarray()}['lose']; var_dump($yo); This yields a parse error. function returnarray() { return array('lose' => array(5,6), 'win' => array(9,8)); } $yo = ${returnarray()}['lose']; var_dump($yo); This gives notices as the result of returnarray() is being converted to a string. $yo === NULL...not what i want. function returnarray() { return array('lose' => array(5,6), 'win' => array(9,8)); } $yo = returnarray()->['lose']; var_dump($yo); This yields a parse error. function returnarray() { return array('lose' => array(5,6), 'win' => array(9,8)); } $yo = ${returnarray()}->['lose']; var_dump($yo); This yields a parse error. Thanks for your help in advance. --PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php

This is not possible in PHP, though you can have a Array wrapper class function returnarray() { return new ArrayObject( array('lose' => array(5,6), 'win' => array(9,8)) ); } var_dump (returnarray()->offsetGet('lose')); or even better make you own wrapper class with __set() and __get() methods so you can have var_dump (returnarray()->lose); of course only in PHP5 Bojan Tesanovic http://www.carster.us/