Re: Return an Array and immediately reference an index

Casey wrote:

On Sat, Apr 12, 2008 at 9:35 AM, Nathan Nobbe <quickshiftin@gmail.com> wrote:

On Sat, Apr 12, 2008 at 12:18 PM, Casey <heavyccasey@gmail.com> wrote:

On Sat, Apr 12, 2008 at 9:12 AM, Nathan Nobbe <quickshiftin@gmail.com>

wrote:

On Fri, Apr 11, 2008 at 6:33 PM, Daniel Kolbo <kolb0057@umn.edu> wrote: search the archives ;) http://www.mail-archive.com/php-general@lists.php.net/msg224626.html -nathan

<?php function ReturnArray() { return array('a' => 'f', 'b' => 'g', 'c' => 'h', 'd' => 'i', 'e' =>

'j');

} echo ${!${!1}=ReturnArray()}['a']; // 'f' ?>

ya; i never did sit down and try to figure out how that works; care to explain ? -nathan

<?php echo ${!${!1}=ReturnArray()}['a']; ${!${!1}=ReturnArray()}['a'] !1 resolves to false. ${!${false}=ReturnArray()}['a'] false resolves to... I don't know. Let's just say false resolves to "a". ${!$a=ReturnArray()}['a'] $a is now the array. The ! changes the returned array into the boolean false (like: if (!$handle = fopen('x', 'r')) { echo 'connection failed' }. ${false}['a'] I don't know what false resolves to, but we're using "a". $a['a'] ?>

Just awesome! Thanks for the explanation Casey, and thanks for the archived link Nathan. I knew I'd learn something by asking.