Re: Scalar type hinting

On Mon, February 27, 2012 10:45 am, Ángel González wrote: > On 27/02/12 17:19, Richard Lynch wrote: >> PRESUMPTION: >> >> *ANY* strict datatype could also be NULL, to represent a failure >> condition... >> >> Otherwise, when you are out of RAM: >> strict $o = new Object(); //violates strict, because Object HAS to >> be >> NULL, as there is no RAM left for it to be an object. > Uh? No. You would get a fatal error because PHP exceeded maximum > allowed memory. You are correct. I'd have to come up with some OTHER scenario not involving fatal error, such as: strict $db = new DB(); and your database being down, unavailable, or connection parameters being wrong. The principle remains. You probably still want $db to be NULL in that situation, rather than an unusable DB object. Otherwise, you'll have to write a lot more sanity checking code elsewhere, which is what you are trying to avoid in the first place... Or, perhaps not. Perhaps you really do want this case to just plain bomb out with a failure that the $db is not strictly an object, with no recourse to try again, or deal with the error in application logic... -- brain cancer update: http://richardlynch.blogspot.com/search/label/brain%20tumor Donate: https://www.paypal.com/cgi-bin/webscr?cmd=_s-xclick&hosted_button_id=FS9NLTNEEKWBE