Re: Scalar type hinting

On Wed, Feb 29, 2012 at 7:08 AM, Michael Morris <dmgx.michael@gmail.com> wrote: > Agreed.  If conversion can occur without data loss (that is, if the > value being assigned is == the value that actually IS assigned) then > no error should occur. > > So > > int $a = "1"; // no error.  1 == "1" so who cares? > int $a = 'House'; // error 0 != 'House', so this is a problem. Actually, 0 == 'House' ;-) > > Again, errors should only raise if the final value != source value. > > On Tue, Feb 28, 2012 at 6:03 PM, Rick WIdmer <vchkpw@developersdesk.com> wrote: >> On 2/28/2012 2:58 PM, Kris Craig wrote: >> >>> strong int $a = "1"; // Converts to 1.  May or may not throw an error >>> (I'm >>> still on the fence). >> >> >> It this is an error, it is no longer PHP. >> >> >> -- >> PHP Internals - PHP Runtime Development Mailing List >> To unsubscribe, visit: http://www.php.net/unsub.php >> > > -- > PHP Internals - PHP Runtime Development Mailing List > To unsubscribe, visit: http://www.php.net/unsub.php > -- -- Tjerk