RE: [PHP] imagecreatefromjpeg: "No JPEG support in this php build"

> The --with-jpeg-dir parameter is used by several apps. Each one mentions > it, which is possibly a point of confusion. In any case, the > user-contributed comments are quite often correct. So yes, you need the > --with-jpeg-dir parameter. Well, I finally got everything to compile ok with what APPEAR to be the correct "--with" pareamters: (--with-gd=/usr/local --with-jpeg-dir=/usr) Two interesting thing of note: 1) When I tried to specify the location of the gd library (which is in /usr/local/lib), you MUST leave OFF the "lib" part of the directory tree or it won't find the library??!! (eg --with-gd=/usr/local/lib WON'T work but --with-gd=/usr/local WILL.... <shrug>). 2) As far as I can tell, the jpeg library I'm after is "libjpeg" which is located in /usr/lib/libjpeg.so.62.... HOWEVER, when I tried configuring apache it kept saying it couldn't find libjpeg... so I took a wild guess and put in a symbolic link to /usr/lib/libjpeg.so to /usr/lib/libjpeg.so.62 and sure enough the darn thing configured/compiled.. BUT, my imagecreatefromjpeg function STILL doesn't work GHAAAA!!!! Getting frustrated here... what am I doing wrong?? Thanks all (especially you Matt!)! -Marc-