why does exit() print its argument?
| From: | Jim Winstead | Date: | Fri, 28 Sep 2001 18:48:35 +0000 |
| Subject: | why does exit() print its argument? | ||
| Groups: | php.dev | ||
| Request: | Send a blank email to php-dev+get-66782@lists.php.net to get a copy of this message | ||
in Zend/zend_execute.c, line 2387, why are we printing the value
passed to exit? writing scripts in php for use outside of a web
server, it would be nice to be able to set the exit value without it
getting printed.
jim