Re: why does exit() print its argument?
| From: | Zeev Suraski | Date: | Sat, 29 Sep 2001 01:18:27 +0000 |
| Subject: | Re: why does exit() print its argument? | ||
| References: | 1 2 3 4 5 | Groups: | php.dev |
| Request: | Send a blank email to php-dev+get-66811@lists.php.net to get a copy of this message | ||
At 03:10 29-09-01, Jim Winstead wrote:
On Sat, Sep 29, 2001 at 02:12:51AM +0200, Zeev Suraski wrote: Uhm, I'm not dumb :) Of course it enables you to do that, but that's the wrong place to put it. exit() has, since its introduction, been a complete equivalent of die(), and had nothing to do with exit statuses. Putting this code there was wrong (even though who knows, maybe I even did that). no, sascha did. php3 does the same thing.Ok, looks like it's old enough (as old as mid 1999). We should probably leave it at that and introduce a new shell_exit() function. Zeev